Question

Using either ∡C or ∡A of △CBA shown below, create three different trigonometric ratios using sine, cosine, and tangent. You must provide the ratio and demonstrate the work used to solve for a missing piece of the ratio. Round all solutions to the nearest hundredth.
(Image being added shortly)

Answer 1

1) you should label the side opposite their vertices with the lower case letter, for example the side opposite of B would be b, opposite of A would be a, etc.

2) remember SohCahToa: or that

Sine= Opposite side/Hypotenuse --> SOH

Cosine= Adjacent side/Hypotenuse --> CAH

Tangent = Opposite side/ Adjacent side -->TOA

so the Sine of angle A would be the ratio between the opposite side and the hypotenuse or
sin(A) = a/b

and repeat for everything

Answer 2

Do you go to connexus if you do ill help becase ive taken those test just tell me what unit and lesson

Answer 3

yes i do ! lol its Unit 4 Lesson 3 in Geometry

Answer 4

ohh well nvrmind sorr she still grading mine

Answer 5

lol thats okay

Answer 6

Do you have have answers yet? And is the triangle assumed to be a 45/45/90 triangle? Only one measurement is actually given. You can definitely set up the equations using the different sine functions stated previously, but to get an answer to the nearest hundredth I feel like there is not enough info

Answer 7

the picture i attached is all there is ... im sorry :/ and no i dont have any answers yet .. i've been stuck on this since yesterday ..

Answer 8

\[\sin A = \frac{ a }{ b }\]\[\cos A = \frac{ c }{ b }\]\[\tan A = \frac{ a }{ c }\]I don't see how you could get an answer without making some sort of assumption. All that is given to us is <B=90