3(x-3)=4(x+_3)
is that supposed to be a "minus" before the last "3"? Like: 3(x - 3) = 4(x + (-3) )
no negative
what is the underscore symbol supposed to mean then?
i was trying to find the negative button but clicked wrong one
so it's a "negative 3" ?
yep
So, this is your equation: 3(x - 3) = 4(x + (-3) ) that last 3 is a "negative 3" if you look at the extra parenthesis I put around it... First, you should multiply the parenthesis stuff out on each side of the equation: 3(x - 3) = 4(x + (-3) ) 3x - (3)(3) = 4x + 4(-3) Then simplify: 3x - 9 = 4x - 12
thanks for help
Glad to help... does it make sense?
You still have another couple steps after where I left it above... collecting the x terms and the number terms, then solving for x.
yes clearly
Yes, clearly, but if you know how to do it, that's great... if you don't, then I can help more. I wasn't wanting to do all your work for you... helps you learn it better if you try some of it as well.
please i m still confuse can u clear me
Just to put it all in one place, I will start over: 3(x - 3) = 4(x + (-3) ) 3x - (3)(3) = 4x + 4(-3) <<--- multiplying out the parenthesis terms 3x - 9 = 4x - 12 <<<--- simplifying by multiplying 3*3=9 and 4*(-3) = -12 3x - 3x - 9 = 4x - 3x - 12 <<<--subtract 3x from both sides to get all the x terms on the right side -9 = x - 12 <<---- simplify by realizing 3x-3x=0 on the left and 4x-3x = x on the right -9 + 12 = x - 12 + 12 <<<--- add 12 to both sides to get all numbers on left 3 = x <<<--- simplify: -9+12=3 (left side) and -12+12=0 (right side) x = 3 <<<--- switch left and right sides (not necessary, unless your teachers have told you that's required.
perfect thanks a lot or explanation
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