Question

Can someone please help me with this: A wheel rotates with a constant angular acceleration of 3.45 rad/s2. Assume the angular speed of the wheel is 1.90 rad/s at ti = 0. (a) Find the angle through which the wheel rotates between t = 2.00 s and t = 3.80 s. (b) Find the angular speed when t = 3.80 s. (c) What is the magnitude of the angular speed FIVE revolutions following t = 3.80 s? I NEED HELP WITH PART C. Thanks.

Answer 1

see if you can get C on your own...

Answer 2

use results from the first three parts...

Answer 3

I don't know where to start

Answer 4

you have omega i, alpha and theta... you want to find omega f.
which equation is going to work?

Answer 5

you only have four choices, so it shouldn't be too hard...

Answer 6

I converted five revolutions into radians then solved Wi t + 1/2at^2 for t. then I used t in Wi + at = W but its not the right answer

Answer 7

\[\omega^2 _{f}=\omega^2 _{i} +2 \alpha \theta \]

Answer 8

yes, 5 rev.s = 10pi radians

Answer 9

initial omega is the result you found in B

Answer 10

alpha is 3.45

Answer 11

So θ in this equation would be 10pi?

Answer 12

yep

Answer 13

Thanks!!