integrate
W=∫[C] F•dr, where dr=dx*i+dy*j+dz*k W=∫[C] Fx*dx+Fy*dy+Fz*dz=∫[C] x*dx+y*dy+z*dz where F=(Fx,Fy,Fz)=(x,y,z)... Basically it is a line integral.
You know any line integral methods? I LOVE green's myself. ;)
@chemENGINEER i love green too, igot 11pi/4-4before, but its not the right answer, im still trying it, anyway ,thx a lot
I see, did you interate on 0 to pi/2? That is the necessary parameters.
@chemENGINEER of course i did, then i got 11pi/4-4
i am just wondering if I use F, is it equal to (ti+tj+tk)?
@chemENGINEER ?
hmm i am just pondering the theory here. It is also notable that F=(gradient)f
is it df/dxi+df/dyj+df/dzk ?
Do you know how to use gradients?
yes, so then do the line integral over f
what i did is: integrate from 0 to pi/2 2tcost+2tcostsint+9tcost(sint)^2 @chemENGINEER
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