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find dy/dx from y = e^-x * lnx
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Hmm so we certainly have product rule on this one! :D Unlike the last heh
Is the ln(x) in the exponent or a seperate term?
yea i did product rule and had -e^x *lnx + e^-x *1/x
Yah looks good! :) Pshhh you don't need our help, yer doin fine \:D/
Oh oh tiny mistake, i see :O hmm
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When you take the derivative of the exponential term, it stays the same right? And you also multiply by the derivative of the exponent (by the chain rule). So that's where the negative sign came from, from the chain rule. But your exponent should still be -x! :O
oh i forgot the - on the exponent? that's it? lol
yah :3 heh looks good besides that.
-e^-x * lnx is just -x right?
@zepdrix ?
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o sorry didn't see yer message :3
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