Question

Calculate the derivative of the function.

h(x) = 9 / (x^2+x+1)^2

Answer 1

did you try the quotient rule?

Answer 2

it's pretty straightforward here...

Answer 3

Hmm this looks just like the last one chris :) nice problem to apply the power rule on (if we first deal with getting that term to the numerator).

Answer 4

\[\frac{ f }{ g }'=\frac{ f'g-g'f }{ g^2 }\]

Answer 5

\[\frac{ -9(x^2+x+1)^2 }{ (x^2+x+1)^4 }\]

Answer 6

yea i have to use the chain rule again

Answer 7

i just have a hard time using the chain rule for this one

Answer 8

no i used qoutient rule

Answer 9

chain rule will look like\[h(x)=9(x^2+x+1)^{-2}\]
\[\frac{ (-2)9(2x+1) }{ (x^2+x+1)^3}\]

Answer 10

\[\frac{ -9[(x^2+x+1)^2]' }{ (x^2+x+1)^4 }=\frac{ -2(9)(x^2+x+1)(2x+1) }{ (x^2+x+1)^2 }\]finally sorted

Answer 11

you wouldnt multiply -2(9)?

Answer 12

-18

Answer 13

im sorry but i plugged that into my assignment and it was incorrect

Answer 14

try this\[\frac{ -18(2x+1) }{ (x^2+x+1)^3 }\]

Answer 15

sorry its still incorrect, are you presenting the right material?

Answer 16

i wouldn't use the quotient rule for this one because the numerator is a constant
just butting in ....

Answer 17

Hmmm the answer Jonask gave you looks correct. I'm not sure why it's not accepting your answer. Maybe you're having trouble typing the format in correctly? :o