Question

find dy/dx from y = 2x^3 * ln(ax)

Answer 1

yayy another product ruleeee

Answer 2

What part you getting stuck on? :O

Answer 3

\[(fg)'=f'g+fg'\]

Answer 4

with
\[f(x)=2x^3,f'(x)=6x^2,g(x)=\ln(ax), g'(x)=\frac{1}{x}\]

Answer 5

@ zepdrix, i just need to check my answers lol... i keep thinking that i did things wrong

Answer 6

Oh i see :)

Answer 7

isn't it chain rule with ln(ax)?

Answer 8

i meant product rule?

Answer 9

chain rule? :o oh yes i suppose it is.
\[[\ln(ax)]'=\frac{ 1 }{ ax }(ax)'=\frac{ 1 }{ ax }a=\frac{ 1 }{ x }\]
But you still get what satalite posted :3 after simplifying.

Answer 10

Well hopefully they intended for A to be a constant, which is why we wouldn't apply the product rule :O it's not a variable thingy

Answer 11

well there's no where that says a is a constant :(