x^2-19x-120
Factor -120, find a factor pair ab that adds to -19, use those to represent the trinomial as the product (x+a)(x+b).
I understand the process but I am wracking my brain trying to figure out which pair I should use...
\[x^2-19x-120=(x+ a )(x+ b)=x^2+(a+b)x+ab\] \[ab=-120\] \[a+b=-19\]
\[-120=\pm1\times\mp120,\quad\pm2\times\mp60,\quad\pm3\times\mp40,\quad\pm4\times\mp30\]\[\qquad\qquad\pm5\times\mp24,\quad\pm 6\times\mp20,\quad \pm 8\times\mp15,\quad \pm10\times \mp12\]
which pair of factors add to give negative nineteen?
Thank you unklerhaukus I just realized while looking at your pairing that I had left one out and that is why I was not getting my answer the factors are 5 & 24
which one is negative
24
right, so what does \(x^2-19x-120\) look like in factored form ?
(x+5)(x-24)
to check if your got it right , expand the brackets \[(x+5)(x-24)=x(x-24)+5(x-24)\]\[\quad\qquad\qquad\qquad=x^2-24x+5x-120\]\[\quad\qquad\qquad\qquad=x^2+(-24+5)x-120\]\[\color{orange}{BINGO}\]
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