An electronics store makes a profit of $72 for every television sold and $90 for every computer sold. The manager’s target is to make at least $360 a day on sales from televisions and computers. Write a linear inequality and graph the solutions. What are three possible solutions to the problem?A)(5, 2), (3, 3), and (1, 4) are three possible solutions B)(4, 0), (2, 2), and (1, 1) are three possible solutions. C)(3, 1), (2, 2), and (1, 0) are three possible solutions. D) (4, 0), (3, 3), and (1, 4) are three possible solutions
@UnkleRhaukus could you help me figure this out i got b but i was wrong
Profit = $72 x TV + $90 x Computers \[360≤ 72t+90c\]
???
simplify the in-equation, divide both sides by any factors common to all terms ,
can you see a common factor ?
no
nine is a common factor
where did you get 9
|dw:1351748443793:dw|
so the greatest common factor is 2x3x3
now im lost
do you understand any of what i have done?
do you see how i got the in-equation/?
no i dont im sorry
ok, so. the electronic store make Profit for the sale of a TV or the sale of the Computer for every TV sold the profit is $72, for every Computer solde the profit is $90 hence; Profit = $72 x TV + $90 x Computers
the total profit is 72$ times the number of tv's sold and 90$ time the number of computeres sold
the manager wants the profit to be at least 360$
ie, the profit is 360$ or greater
ok so far this has nothing to with the answers i have up or does this help get the answer
if \(t\) is the number of tvs sold and \(c\) is the number of computers sold we can arrive at this in-equation \[360≤72t+90c\]
dont look at the answers, look at the problem
also is there a simpler way for you to explain this cause im not getting it
Join our real-time social learning platform and learn together with your friends!