Question

Solve the equation in the intervals [0,2pi)
sinx-cosx-tanx=-1

Answer 1

Rewrite tan as sin over cos

Answer 2

ok do i need to do common denominators?

Answer 3

Yep multiply every term by cos (I will ignore the x) and because you are multiplying both sides of the equation that is the end of cos on the bottom line !!

Answer 4

i got cosxsinx/cosx-cos^2x/cosx-sinx/cosx=-1

Answer 5

I'll use equation and give you my first two lines, stay patient

Answer 6

\[sinx-cosx-tanx=-1\]
becomes
\[sinxcosx-\cos^2x-sinx=-cosx\]

Answer 7

all over cos?

Answer 8

No, because both sides of the euation were multiplied by cos, the "over cos" was cancelled out.

Answer 9

ok so i add cos to both sides to get everything equal to 0

Answer 10

Excellent, the group into pairs and take out a common factor

Answer 11

awesome ok

Answer 12

Okay whats next?