Question

Which pair has equally likely outcomes? List the letters of the two choices below which have equal probabilities of success, separated by a comma. A standard deck of cards has 12 face cards and four Aces (Aces are not face cards).

A. drawing a black two out of a standard 52 card deck given it’s not a face card or an Ace.
B. drawing a six out of a standard 52 card deck given it’s not a face card or an Ace.
C. rolling a sum of 7 on two fair six sided dice
D. rolling a sum of 3 on two fair six sided dice
E. rolling a sum of 10 on two fair six sided dice

Answer 1

this is maybe the tenth time i have seen this strange question
where does it come from?
you have 5 probabilities to compute, so it is a pain

Answer 2

ughhh it's something crazy I just can't seem to understand it

Answer 3

A has probability \(\frac{1}{2}\) since half the cards are black
B has probability \(\frac{4}{36}=\frac{1}{9}\) since you have 6 sixes in a deck without the 16 face cards or aces

Answer 4

I got A correct but when it comes to the other ones I don't understand it very well

Answer 5

there are six ways to get a 7 on two dice, 36 possible rolls, so probability of C is \(\frac{6}{36}\)

Answer 6

which ones are not clear?

Answer 7

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Question 386490: Which pair has equally likely outcomes? List the letters of the two choices below which have equal probabilities of success, seperated by a comma. A standard deck of cards has 12 face cards and four aces (aces are not face cards). Please show your probability for each choice below.
a) drawing a red five out of a standard 52 card deck given it's not a face card or an ace.
b) rolling a sum of 10 on two fair six sided dice.
c) rolling a sum of 3 on two fair six sided dice.
d) rolling a sum of 7 on two fair six sided dice.
e) drawing a four out of a standard 52 card deck given it's not a face card or an ace.

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Answer by ewatrrr(10589) (Show Source):
You can put this solution on YOUR website!

Hi,
a) drawing a red five out of a standard 52 card deck given it's not a face card or an ace.
52 - 4aces - 12face cards = 36 possibilities P = 2/36 = 1/18
e) drawing a four out of a standard 52 card deck
given it's not a face card or an ace. 4/36 = 1/9
b) rolling a sum of 10 on two fair six sided dice. P = 3/36 = 1/12
c) rolling a sum of 3 on two fair six sided dice. P = 2/36 = 1/18


d) rolling a sum of 7 on two fair six sided dice. P = 6/36 = 1/6
a,c have equal probabilities of success
___1_2_3__4__5__6
1|_2_3_4__5__6__7
2|_3_4_5__6__7__8
3|_4_5_6__7__8__9
4|_5_6_7__8__9_10
5|_6_7_8__9_10_11
6|_7_8_9_10_11_12

Answer 8

wow, that is very helpful, ty so much

Answer 9

is just the whole concept of the problem that I get a little confuse

Answer 10

the number of ways to roll a total of ten on two dice
\((4,6),(6,4),(5,5)\) there are 3 ways out of 36 probability is \(\frac{3}{36}\)
similarly there are 2 ways to roll a total of 3
\((1,2),(2,1)\) so that probability is \(\frac{2}{36}\)

Answer 11

where the hell did that come from?

Answer 12

letter C. 6/36=1/6??? do I have it right?

Answer 13

lol IDK

Answer 14

can you see what I c

Answer 15

aah i see it is a black two for A
there are two of them, out of the 36 remaining cards so that probability is \(\frac{2}{36}\) same as the probability of rolling a 3 on two dice

Answer 16

Hahahaha that was some GREAT TROLLING.

Answer 17

the question asks for the two that are the same
your answer is A and D

Answer 18

your answer is A and D

Answer 19

lol yes it was

Answer 20

ok

Answer 21

question asks
"List the letters of the two choices below which have equal probabilities "

Answer 22

uh? are you giving me a ? if you are where are the choices

Answer 23

o_o

Answer 24

ty all

Answer 25

i think c or d