Express in single log and find the solutions for...
\[\log_{3}x +\log_{3} (x+3)=3+\log_{500} 1\] Please help :/ Thank you :)
wat's so tough? it's easy
log(x)(x+3) base 2 = log500^3 base 500 + log(1) base 500........ can u take it from here?
hint, \(\log_b(1)=0\) because \(b^0=1\) ignore that part
in other words, start with \[\log_{3}x +\log_{3} (x+3)=3\] then combine the left in to a single log, get \[\log_3(x(x+3))=3\] rewrite in equivalent exponential form as \[x(x+3)=3^3\] solve a nice quadratic equation
I understand how to get the \[\log_{3}(x(x+3))=3 \] part, but how do you get \[x(x+3)=3^3\] afterwards?
And @A.Avinash_Goutham obviously I need help, otherwise I wouldnt be here. You dont have to be rude..
rude? i was? sorry o.o
@satellite73? Could you help me a little more please.
Anybody?
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