Question

5^3sqrt(4x −1 + 2 = 17)

Answer 1

\[5^3\sqrt4x −1 + 2 = 17\]

Answer 2

is x under the square root?

Answer 3

yes the sqrt goes to the 1

Answer 4

1st subtract the 2
what do you get

Answer 5

5^3sqrt(4x-1)=17-2

Answer 6

5^3sqrt(4x-1)=17
125sqrt(4x-1)=17
sqrt(4x-1)=17/125
taking square
4x-1=(17/125)^2
4x=(17/125)^2+1
x=((17/125)^2+1)/4

Answer 7

\[5^3\sqrt{4x-1}=15\]
\[\sqrt{4x-1}=15/5^3\]
\[(\sqrt{4x-1})^2=(15/5^3)^2\]
\[4x - 1 = \frac{ 9 }{ 625 }\]
\[4x = \frac{ 9 }{ 625 }+1\]
\[4x = \frac{ 634 }{ 625 }\]
\[x = \frac{ 317 }{ 1250}\]

Answer 8

thank you guys :)

Answer 9

he is wrong because 17-2= 15

Answer 10

oops i made a mistake