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sqrt(4x + 16) = x + 1
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@hartnn
take square on both sides
yes i got that. This is what I have so far: square both sides 4x+16=x^2+0 4x+16=x^2
You made a mistake
which part?
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it would be x^2+2x+1
for the right side
oh oops that is rigt :P i just typed it wrong lol thank you
So, what would you do next?
I dont know. I'm stuck after that. That's why i'm asking for help :P
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shift x on left side and constant values on right
You should rearrange to get x^2+2x+1=4x+16, Then x^2-2x-15=0
Then factor that last equation.
(x+3)(x-5)=0
4x+16=x^2+2x+1 4x-2x-x^2=1-16 -X^2+2x=-15 x^2-2x=15 x^2-2x+15 now made factors
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@03225186213 You made a little mistake towards the end. it would be x^2-2x-15=0. Otherwise that's correct.
oops thanks
(x+3)(x-5)=0 x=-3 x=5
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