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Mathematics 6 Online
OpenStudy (anonymous):

Can someone help me with this 3 part Math Problem? You work at a public golf course you have a budget of $300 for supplies for the month. A) The golf course can buy golf balls at a price of $.80 each. Write an inequality that states the number of golf balls you can buy at this price and still have $200 left in your budget for other items. B) Use the equation from part A to solve for the maximum number of golf balls you can buy and still have $200 left in your budget

OpenStudy (anonymous):

C) After buying golf balls you have $200 left over now you need to buy a few replacement golf clubs. You can get these for $22 each. Write an inequality and solve it to find the maximum number of golf clubs you can buy and still have $40 left over in your budget.

OpenStudy (anonymous):

Let g=golf balls $.80 each so .80g, that has to be less than or equal to $100 so you can have 200 left over... \[.80g \le100\]

OpenStudy (anonymous):

Solve the inequality to get part b

OpenStudy (anonymous):

I solved it and got g<= 125 @CalebBeavers

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

So that would be the answer to. part B??

OpenStudy (anonymous):

Yep 125 would be the answer

OpenStudy (anonymous):

Okay! So for Part C would I do 200-22g = 40 ????

OpenStudy (anonymous):

No, its like part b. You can spend $160 and have $40 left over, 22 per golf club or 22x has to be less than or equal to 160. \[22x \le160\]

OpenStudy (anonymous):

Oh okay.... I got x <= 80/11

OpenStudy (anonymous):

@CalebBeavers

OpenStudy (anonymous):

Yeah just round it to 7

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