Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 7, -11, and 2 + 6i f(x) = x4 - 53x2 + 468x - 3080 f(x) = x4 - 9x3 - 42x2 + 234x - 3080 f(x) = x4 - 117x2 + 468x - 3080 f(x) = x4 - 9x3 + 42x2 - 234x + 3080 i really need help understanding this one
create a set of products by subtracting x from the given zeros
the complex zero has an extra root that tags along with it so dont forget to bring it along
and how do i do that
(a+bi) <--> (a-bi) complex zeros come in pairs; and the only difference in their appearance is a change in operator
zeros are: 7, -11, 2 + 6i, 2 - 6i subtract and x from each zero 7-x, -11-x, 2 + 6i-x, 2 - 6i-x and multiply them all together (7-x)(-11-x)(2 + 6i-x)(2 - 6i-x)
ok thank you
youre welcome if you wanna double chk your work .... http://www.wolframalpha.com/input/?i=%287-x%29%28-11-x%29%282+%2B+6i-x%29%282+-+6i-x%29
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