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Calculate how many grams of oxygen form when each quantity of reactant completely reacts. 2HgO----->2Hg+O2
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a) 2.13 g Hgo b) 6.77 g Hgo c) 1.55 kg Hgo d) 3.87 mg Hgo
HgO ******** on those
You're given a balanced equation 2 moles of HgO formes 1 mole of O2 so then take your masses for each one (first convert all to g) to moles of HgO = ? mass (use periodic table to find M.W. of HgO and convert to moles) Afterwards stoichometry to find moles of O2 then mass of O2 using M.W. of O2
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