Question

lim x-> infinity (3x/1+2x^2)^x

Answer 1

the answer is zero

Answer 2

i dont need answers..

Answer 3

i need to do the steps.. i have answers too

Answer 4

\[y=\lim_{x \rightarrow \infty} \left( \frac{ 3x }{ 1+2x^2 } \right)^x\]

Answer 5

apply ln to both sides of the equation, then evaluate the limit at infinity

Answer 6

that's what i did too

Answer 7

\[\ln y=-\infty \]

Answer 8

why...
and since ln(3x / 1+2x^2 ), can't u do ln3x - ln(1+2x^2)

Answer 9

\[\lim_{x \rightarrow \infty}\ln \frac{ 3x }{ 1+2x^2 }=-\infty \]

Answer 10

splitting the fraction would only cause you trouble

Answer 11

how do you know that it goes to -ve infinity?