Describe the transformation for : y= -x²+6x-5
The parent function is the squaring function, \(y=x^2\) Look at all the ways \(y= -x^2+6x-5\) is different from the parent function. Putting it in vertex form will also help.
how do i do that ? :$
Vertex form? Complete the square.
ohhh okay !
\[\huge -(x-3)^2+4\]
That looks right.
\[\huge Range = {\epsilon \mathbb{R}| y \neq 0}\]
Not for the function you have above, no.
y doesnot equal 4** sorry typo
y can equal 4 here, just not anything above it.
my solution says it says y can equal any real number :S
yeah i thought it was that too,
Not for a parabola it can't.
The domain is any real number for x...
yeah that's what i thought, look at number 8 http://mail.wecdsb.on.ca/~janet_maitland/FOV1-0006CFBC/FOV1-0006E9C7/unit%20three%20practice%20answers.pdf?Plugin=Loft
maybe she made a mistake :S
Yeah, you can see clearly from the graph that the range is y≤4.
okay thanks :D i thought i might have been doing to wrong
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