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Mathematics
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Log derivatives
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4^3x
\[4^{3x}=e^{3x\ln(4)}\] take the derivative using the chain rule
or perhaps you have memorized \[\frac{d}{dx}b^x=b^x\ln(b)\] in which case you can go right to the answer, again by the chain rule
not exactly clear why you have "log derivatives" if it was something like \[x^{2x}\] you would need logarithmic differentiation, but this one really just needs the chain rule \[4^{3x}\ln(4)\times 3\]
well my teacher listed log problems i had to derive, this happens to be one of them
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isn't it 3(ln4)4^3x?
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