The barrel of a rifle has a length of 0.845 m. A bullet leaves the muzzle of a rifle with a speed of 568 m/s. What is the acceleration of the bullet while in the barrel? A bullet in a rifle barrel does not have constant acceleration, but constant acceleration is to be assumed for this problem. Answer in units of m/s 2
What is acceleration?
Ok, it is the rate of change of velocity
what is the change of velocity for the bullet
Well it starts at 568 m/s what I'm trying to find is the acceleration, or change of the bullets velocity
It starts at rest that is zero. when it leaves the gun it is 568m/s
SO we have initial velocity U, final velocity V we have distance travelled during acceleration S .
Using the equations of motion \[V ^{2}=U ^{2} + 2AS\]
We Make A subject of the formula
alright so would it be 568^2=0^2*2(?)
A=\[\frac{ V ^{2}-U ^{2} }{ 2S }\]
Sub your values for V U and S to get your acceleration
okay so V is 56862 U is 0 but what is S?
S is the distance travelled in acceleration 0.845m
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