If you overshoot the endpoint in titration of the KHP, how would the calculated value for the molarity of the NaOH solution be affected?

Question

anonymous · Answer

Ok, so we know that at neutralization the amount of acid = amount of base
However, if you overshoot and end up using too much base, your volume would increase for amount of NaOH used.
What would that do to your molarity? (Hint M= n/L)

anonymous · Answer

Wouldn't it make it smaller than its true value?

anonymous · Answer

so because you have a higher volume of NaOH, the amount/higher volume would yield a lesser concentration, so yes you're correct

anonymous · Answer

i know the answer.. i just don't understand the reasoning behind it..

anonymous · Answer

Molarity = moles/volume
if you have more volume, your Molarity will decrease, basic fraction property

anonymous · Answer

got it! thanks!