Question

find exact values of the expression

2sin(pi/12)cos(pi/12)

Answer 1

\[2\sin \frac{ \pi }{12 }\cos \frac{ \pi }{ 12 }\]

Answer 2

\[\sin \frac{ \pi }{ 6 }\] or 1/2 or 0.5

Answer 3

hows you get that?

Answer 4

identity

Answer 5

\[\sin 2A=2\sin A \cos A\]
\[A=\frac{ \pi }{ 12 }\] in your problem

Answer 6

do i divide by 2?

Answer 7

the right side of the identity is your given, the left side will be the answer

Answer 8

use A=pi/12

Answer 9

so its \[\frac{ 2 }{1 } \times \frac{ \pi }{ 12 }\]

Answer 10

that's pi/6 when simplified

Answer 11

okay i got it, how would you simiplify tan pi/8

Answer 12

the property changes \[8\log_{8}30 \] to \[8\log_8 2 + 8\log_8 3 + 8\log_8 5\]

Answer 13

oops, wrong tab. hahaha

Answer 14

ohh lol i was like what

Answer 15

\[\tan \left( \frac{ \pi }{ 8 } \right)=\tan \left( \frac{ 1 }{ 2 } *\frac{ \pi }{ 4 }\right)\]
then use the identity for half-angle of tan

Answer 16

the \[\tan \frac{ u }{ 2}= \frac{ 1-cosu }{ sinu } \]

Answer 17

no square on tangent?

Answer 18

it doesnt have one in the book

Answer 19

or do i use tan2x=2tanx/1-tan^2x

Answer 20

the first formula is correct. and use it

Answer 21

how do distinguish between which one is sinu or cosu

Answer 22

\[\tan \frac{ \pi }{ 8 }=\tan \left( \frac{ \pi/4 }{ 2 } \right)\] use \[u=\frac{ \pi }{ 4 }\] on both sine and cos

Answer 23

okay

Answer 24

after i get\[1-\frac{ \sqrt{2} }{ 2 }/\frac{ \sqrt{2} }{ 2 }\] what should i do?

Answer 25

rationalize the denominator by multiplying both sides by sqrt(2)

Answer 26

got to go. i see raised eyebrows. hahaha