How do I find the critical numbers of f' from the graph of f''?
I know how to find the critical numbers for the graph of f from f', but this is asking for the critical numbers of f' from f"", which I don't know how to do.
^*f"
if you know how to find the critical numbers of f with information from f', then you can apply that same knowledge with the second derivative and apply it to f'... put it this way... let g=f' then g' = f'' if you know the where g' is zero, that's the critical numbers of g...
RIght, I know that where ever x=0 on the graph of f', then those values are critical numbers of f. But how do I go about finding the critical numbers of f' just by looking at the graph of f''?
let f' = g, so f'' = g' ... g' = 0 means f'' = 0. so "whereever g'=0 that's the critical numbers for g." same statement: "whereever f''=0 that's the critical numbers for f'."
So it's kind of the same process as finding the critical numbers of f from the graph of f''? The critical numbers of f' are where x=0 on f''?
*from the graph of f'
^type
*typo
exactly...
So since x=0 four times on the graph of f'', then there are four critical numbers of f'?
yes...
Ah. I guess I was just expecting the process to be different for second derivatives and such. Well thanks.
btw... you mean f''=0 four times on the graph, then there are four critical numbers of f'
Oh yes, that's what I mean. Thanks.
yw...)
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