Question

just checking

Answer 1

given
E=\[\sqrt{2}\sqrt{2-\sqrt{3}}(\sqrt{3}+1)\]
Calculate \[E^{2}\] then deduce the value of E
I got E=2 so did my calculator but wolfram got something else

Answer 2

http://www.wolframalpha.com/input/?i=sqrt+2sqrt%282%E2%88%92sqrt%283%29%29%28sqrt3%2B1%29

Answer 3

You can check your value on the wolfram input box, sometimes there is an error because the radicals are incorrectly put.

Answer 4

\(\large E=\sqrt{2}\sqrt{2-\sqrt{3}}(\sqrt{3}+1) \)
\(\large E^2=(\sqrt{2}\sqrt{2-\sqrt{3}}(\sqrt{3}+1))^2 \)
\(\large E^2=2(2-\sqrt{3})(\sqrt{3}+1)^2=(4-2\sqrt3)(3+2\sqrt3+1) \)
\(\large = (4-2\sqrt3)(3+2\sqrt3+1) \)
\(\large = 12+8\sqrt3+4-6\sqrt3-12-2\sqrt3=4 \)

so E=2...

Answer 5

thx

Answer 6

yw..:)