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Mathematics 13 Online
OpenStudy (anonymous):

just checking

OpenStudy (anonymous):

given E=\[\sqrt{2}\sqrt{2-\sqrt{3}}(\sqrt{3}+1)\] Calculate \[E^{2}\] then deduce the value of E I got E=2 so did my calculator but wolfram got something else

OpenStudy (anonymous):

You can check your value on the wolfram input box, sometimes there is an error because the radicals are incorrectly put.

OpenStudy (anonymous):

\(\large E=\sqrt{2}\sqrt{2-\sqrt{3}}(\sqrt{3}+1) \) \(\large E^2=(\sqrt{2}\sqrt{2-\sqrt{3}}(\sqrt{3}+1))^2 \) \(\large E^2=2(2-\sqrt{3})(\sqrt{3}+1)^2=(4-2\sqrt3)(3+2\sqrt3+1) \) \(\large = (4-2\sqrt3)(3+2\sqrt3+1) \) \(\large = 12+8\sqrt3+4-6\sqrt3-12-2\sqrt3=4 \) so E=2...

OpenStudy (anonymous):

thx

OpenStudy (anonymous):

yw..:)

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