Question

Charles's Law of V/T = k were represented in graphical form, what it would look like?j

Answer 1

do you want to plot
\(V(T)=kT\) or \(T(V)=\frac Vk\)

Answer 2

t(v) = v/k.

Answer 3

is of the form\[y(x)=mx+b\]
where

\((x,y)=(V,T)\)

the vertical-intercept is zero

the gradient is \(1/k\)