How do you reduce the following: x-y/x^2-1 times x-1/x^2-y^2?

Question

anonymous · Answer

@satellite73 @Zarkon

anonymous · Answer

20
gabriel13






0@satellite73 @Zarkon

zarkon · Answer

this...

$$\frac{x-y}{x^2-1}\frac{x-1}{x^2-y^2}$$?

anonymous · Answer

YES

zarkon · Answer

notice that $$x^2-1=(x-1)(x+1)$$ and 
$$x^2-y^2=(x-y)(x+y)$$

anonymous · Answer

x^2-1=(x+1)(x+y) is the answer coreect in http://dpslittlejohns.owotw11.com/showAssignment?course_id=o_alg02_2011&assignment_id=o_alg02u05c01l03d&unit_id=5&__athena_reconnect__=1

zarkon · Answer

$$\frac{x-y}{x^2-1}\frac{x-1}{x^2-y^2}$$

$$=\frac{x-y}{(x+1)(x-1)}\frac{x-1}{(x-y)(x+y)}$$

$$=\frac{x-y}{(x+1)\cancel{(x-1)}}\frac{\cancel{x-1}}{(x-y)(x+y)}$$

$$=\frac{x-y}{(x+1)}\frac{1}{(x-y)(x+y)}$$
$$=\frac{\cancel{x-y}}{(x+1)}\frac{1}{\cancel{(x-y)}(x+y)}$$
$$=\frac{1}{(x+1)}\frac{1}{(x+y)}=\frac{1}{(x+1)(x+y)}$$

anonymous · Answer

yes is this thanks

anonymous · Answer

a^3+a2b/5a.25/3b+3a  help me @Zarkon's

anonymous · Answer

@Zarkon's  help me please

anonymous · Answer

a^3+a2b/5a.25/3b+3a