prove that arctan x+arctan y= arctan x+y/1-xy
Can you put parentheses where they belong toward the end of the equation?
is 1-xy over arctan x+y or just under y?
hitthis part of the question i have answered i am struggling with the second part which is slightly tricky. it says use this relationship to show that if arctan (x) + arctan (y) + arctan(z) = pi/2 then xy + yz + zx = 1. i
the relationship is arctan (x) + arctan (y)= arctan (x+y)/(1-xy)
okay
I'm sorry, but I don't think I can help you with that one. Is it supposed to be a system of equations?
i am struggling with simplifying the terms
For the first or second one?
i sthe second one as it will follow the same form as the first one but you have the extra term added arctan z. this is how far i have got
(x+y+z-xyz)/(1-xy-xz+yz)=pi/2
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