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Physics 12 Online
OpenStudy (anonymous):

Two cars that have the same mass and velocity have a head on collision. A car with the same mass and velocity as the first situation crashes into a massive wall. which has more damage?

OpenStudy (anonymous):

When something is damaged, it's often because it could not withstand the energy transfered to it, either because of the high amount, or the way it was transfered. For an electric circuit (or a computer), it can be electric energy (power surge) or physical (a hammer and an angry person). Therefore, if the car is damaged, it's because of the enormous amount of energy that was transfered to it. (I won't get into the other details about fractures, energy dispersion and conversion, but just know that what I've said is not all there is to it, it's just enough for this situation). Now, which collision has more energy put into it? knowing that \[K_{e}=\frac{ 1 }{ 2 } mv ^{2}\] and you have 2 objects colliding and sharing the impact in both situation?

OpenStudy (anonymous):

the first situation has more energy going into it

OpenStudy (anonymous):

exact. because no matter the mass of the wall, it doesn't have any speed, so no kinetic energy.

OpenStudy (anonymous):

In the first situation, there will be more damage done to the car

OpenStudy (anonymous):

which ever loses more kinetic energy has the most damage correct?

OpenStudy (anonymous):

Very roughly, yes.

OpenStudy (anonymous):

but if your car was made of rubber, all the energy would be absorbed... which is not the case now, I just want you to know that though

OpenStudy (anonymous):

everywhere i looked it says that the two crashes have the same amount of damage

OpenStudy (anonymous):

What course is it?

OpenStudy (anonymous):

college physics

OpenStudy (anonymous):

The total amount of energy in this system is found by using the kinetic energy equation (KE = ½ mv2). So KE = (2)(1/2 mass)(v2). The KE equation is multiplied by two because there are two cars in the system with equal values of m and v. This equals the same total amount of energy as the car and wall collision, meaning that neither collision did more damage. There was the same amount of damage in both systems.

OpenStudy (anonymous):

but for the wall the wall would have zero final velocity correct? canceling its KE?

OpenStudy (anonymous):

I don't know what they assumed when they wrote this, but when organizations do collision tests with cars, they throw a car at 64kph at a wall, to simulate a crash between two cars at 50kph.

OpenStudy (anonymous):

yes, 0 initial and 0 final, but still energy will be transfered to it, in the form of internal energy (brick nods will be crushed closer together, building up tension, which requires more energy to sustain) and heat will be evacuated

OpenStudy (anonymous):

im gettin that the first situation will have twice as much damage than the second but everyone is saying im wrong and they are equal

OpenStudy (anonymous):

I guess... for the sake of your exam, believe it. When you get to university, find another answer.

OpenStudy (anonymous):

i wish i took university instead ive already had calculus

OpenStudy (anonymous):

It's the same thing as saying in high school that a block that is pushed will keep on moving forever, because there's no friction. It's a simplification. But this one about the cars is so widespread that even teachers will sometime believe if they haven't studied it.

OpenStudy (anonymous):

ohh, that's right, in US it's either college or university, I forgot

OpenStudy (anonymous):

yea thats how it is here

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