Question

When 4 inches are added to each side of square, its area increases by 64 square inches. What is the area of the initial square?

Answer 1

36

Answer 2

\[A=x ^{2}\]
with x being the length of the initial sides
\[A+64=(x+4)\]

Answer 3

the area of previous square was 36 sq. inches

Answer 4

\[(x+4)^{2}\]
sorry

Answer 5

(x + 4)^2 = x^2 + 64. This will be a quadratic in "x".

Answer 6

how did you get 36 so i can do the rest by myself?

Answer 7

it can be done by trial and error also

Answer 8

(x + 4)^2 = x^2 + 64 will become x^2 + 8x + 16 = x^2 + 64. Just combine terms and simplify.

Answer 9

ok one thing why do you square it

Answer 10

area of square is its side squared

Answer 11

You have to get the area. Both of the first square and the second.

Answer 12

and x is the side

Answer 13

thanks guys

Answer 14

The second area is (x + 4)^2 and the first area is x^2

Answer 15

hmm

Answer 16

its our pleasure

Answer 17

\[A _{1}=x _{1}^{2}\]
\[A _{2}=x _{2}^{2}\]
\[A _{2}=A _{1}+64\]
\[x _{2}=x _{1}+4\]
Does that help?

Answer 18

lol i got it

Answer 19

ok so i did x^2 + 8x + 16 = x^2 + 64. and i got 6 what did i do wrong

Answer 20

you got \[x _{1}=6\]
so what's the area?
Never forget what was the initial question