Question

[5.02] Which of the following is not an equivalent form of the compound inequality

x + 6 > 13 or x + 6 11

x > 7 or x 5
x 5 or x > 7
A number line with an open circle on 7, a closed circle on 5, and shading in between.
A number line with an open circle on 7, shading to the right, and a closed circle on 5, shading to the left.

Answer 1

x + 6 > 13 or x + 6 11
x > 7 or x 5
x 5 or x > 7

Is there a symbol between 6 and 11, and x and 5?

Answer 2

6 <= 11
x <= 7

Answer 3

\[6\le11\]and\[x \le5\]?

Answer 4

yes

Answer 5

Let's solve the first inequality;
\[x+6>13\]
To get x alone, we would first subtract 6 from both sides;
\[x+6-6>13-6\]
\[13-6=7\]
So,
\[x>7\]

Next inequality;
\[x+6\le11\]
To get x alone, we would subtract 6 from both sides again;
\[x+6-6\le11-6\]\[11-6=5\]So,
\[x \le5\]

The answer is ;

A number line with an open circle on 7, a closed circle on 5, and shading in between.

Because the inequality states that x is going to be greater than 7, or less than or equal to 5. The description above states that x is going to be less than 7 and greater than or equal to 5, which is incorrect.

Answer 6

Thanks you!!

Answer 7

You're welcome!