Question

rewrite equation in vertex form
y = x^2 -6x + 4

Answer 1

Are you able to complete the squar on this?

Answer 2

it just says put the equation in vertex form.

Answer 3

Ok, I asked because that's the way to solve. Take half of "b", which is -6 and square it. Then add AND subtract it from the right side only. Can you write that out?

Answer 4

The general technique is this, for equations like this that are in the form y = ax^2 + bx + c -> y = a[x^2 + (b/a)x] + c -> y = a[x^2 + (b/a)x + (b/2a)^2] + c - a[(b/2a)^2] -> y = a[x + (b/2a)]^2 + c - a[(b/2a)^2] -> x = -[b/(2a)] is a vertical line and is your axis of symmetry and the point (-[b/(2a)], c - a[(b/2a)^2]) will be your vertex. Your question here is simplified because "a" is 1, so you can jump right to working with "b", dividing it by 2 and squaring it.