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Calculus1
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Find the Taylor series at a = −4 for f(x) = x4 + 5x2 + 5.
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It's an e^x... but yeah, I don't know where to go from here.
I think you have to use this. \[ \Large \sum_{n=0}^\infty f^{(n)}(a)\frac{(x-a)^n}{n!} \]Where \(f^{(n)}(a) \) is the nth derivative evaluated at a.
I tried that... it's only the first derivative if it asks it like it does?
? only the first derivative?
You do keep doing the derivative until you have a pattern or get to 0
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\[ \begin{array}{l} f^{(0)} = x^4+5x^2+5 \\ f^{(1)} = 4x^3+2*5x \\ f^{(2)} = 4*3x^2+2*5 \\ f^{(3)} = 4*3*2x \\ f^{(4)} = 4*3*2 \\ f^{(5)} = 0 \\ \end{array} \]
Not sure what you mean by it's an \(\large e^x\).
Nevermind, I am being retarded, I got it :) Thank you
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