Part 1: Using complete sentences, explain how to find the equation of the line, in standard form and slope–intercept form, passing through (2,6) and (-4, 8). Part 2: Compare the benefits of writing an equation in standard form to the benefits of writing an equation in slope–intercept form.
what's the first thing you have to do?
Honestly clueless
you have to first find the slope
I just need this answered to be done with my online ALG 2 class
i'm in algebra 2 as well. just started though
sooo slope = -1/3?
yea, so now what do we do?
sub in coordinate points in the equation i guess
yea, we have to put the information now into point-slope form. do you know what that is?
Y=MX+B right
no, that's slope-intercept form
from point-slope form, we can change it into slope-intercept, and then standard
erp. whats point slope?
y - y1 = m(x - x1)
so we can use one of the given coordinates for this. we'll use the first one (2,6)
you substitute the 2 for x1, 6 for y1, and -1/3 for m
is this making sense so far?
x-2 = -1/3(y-6) ?
you switched up the x's and y's point-slope is: y - y1 = m(x - x1) so it would be y - 6 = -1/3(x - 2)
typing error :/ okay now what
so now it's in point-slope...how could we get it into slope-intercept form? y = mx + b?
add 6 to both sides?
well first, i'd distribute the -1/3 into the parentheses, then add 6
so what would it be in slope-intercept form?
the 1/3 is messing me up trying to distribute
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-2/3 right?
positive my bad
yep
so what's 2/3 + 6?
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