Question

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Answer 1

x^4(3/5)
x^12/5

Answer 2

I think you probably need to show the answer in a radical form, not an exponent form.

Answer 3

Although I agree that simplification in exponent form is the best first step.

Answer 4

I don't think that's correct...

You start with x^4^(3/5)
Ignore the 5 in the denominator for a sec...
When you raise "x to the fourth" to the third power, like (x^4)^3 , you get x^12... the exponents multiply.
Now let's use the 5 from the denominator... it just divides the exponent,
so it's (x^12)^(1/5) (remember, we already took care of the 3 in the numerator)
which then is just x^(12/5)

You don't have to do it in two steps... x^4 raised to the 3/5 power means you just multiply the exponent 4 by the other exponent, 3/5, to get 12/5

Answer 5

So you simplify to x^(12/5), which means the "fifth root of x^12"

in radical form, you show it like:\[\sqrt[5]{x ^{12}}\]

Answer 6

At least I think that's correct. :) It's been a bit since I did these.

Answer 7

what do you think @pkjha3105 ? Was that correct? I was actually hoping to watch you solve it so I could remember what to do :)

Answer 8

oh, never mind.. I forgot to simplify the radical.

Answer 9

I think that's closer...
\[\sqrt[5]{x ^{12}} = \sqrt[5]{x ^{5}x ^{5}x ^{2}} = x ^{2}\sqrt[5]{x ^{2}}\]

Answer 10

I'm not familiar with the phrasing of x5 rad 2.

I assume "x5" is x^5, but "rad 2" isn't clear.