Question

find all critical point of f(x)=cos^2+sqrt3sinx

Answer 1

were you able to find f'(x)? :)

Answer 2

its -cos(x) (sqrt(3)+2 sin(x))

Answer 3

\[f'(x)=2cosx(-sinx)+\sqrt3 cosx=cosx(\sqrt3-2sinx)\]
Hmm I don't think there was a negative on the sine term, no? :o

Answer 4

im not sure

Answer 5

(sqrqt3-2sinx)cos(x)

Answer 6

Yah I think that's what you should get :D I think you had 1 too many negative signs in your original answer

Answer 7

So to find critical points, we set this derivative equal to zero and solve for the different x values, yes? :D

Answer 8

can we do it together

Answer 9

is it pi/3, and -pi/3

Answer 10

Hmmm I think these are the values we get D: