∫∫∫ dV = (4/3) πr³
The flux is going to be the surface integral of the vector field. I think that's what you want
change to spherical coordinates
i use the divergence theorem to calculate it, but i got 700pi for this, its not the right answer
does it say you are supposed to use the divergence theorem?
no but i tried to use that method....
could u please show me ur method?
I think the divergence theorem should work, I was just asking...
but my answer is not right, i already calculate it many times
\[\iint\limits_S\vec F\cdot d\vec S=\iiint\limits_E\text{div}\vec FdV\]\[\text{div}\vec F=1-1+5=5\]\[\iiint\limits_E\text{div}\vec FdV=5\iiint\limits_EdV\]is this what you had?
yes
and ∫∫∫ dV = (4/3) πr³=(4/3)pi 1^3=4pi/3
I don't see how you are getting that result for your integral, what bounds are you using?
and then its 20pi/3
yeah
oh!!!! i got the wrong radius!!!
well that'll do it :P
sry!!!! i really made a stupid mistake
thx a lot !!!!
haha, it happens to us all no prob!
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