Forces: You discover that it takes 258.0 N to set a 40.0 kg crate in motion on a concrete surface. What is the coefficient of static friction for the crate?
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OpenStudy (anonymous):
@ swin u need to know what plane u are working on is it an incline plane or an horizontal plane/
OpenStudy (anonymous):
coefficient of static friction=static frictional force/ normal rection
OpenStudy (anonymous):
I assume the plane is horizontal: the normal reaction=weight=mg ur
OpenStudy (anonymous):
got it buddy?
OpenStudy (anonymous):
@hubertH it doesn't say. so i assumed it was horrizontal
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OpenStudy (anonymous):
so u knw how to get to the answer right?
OpenStudy (anonymous):
but is static friction only involved in inclined plane?
OpenStudy (anonymous):
No.. then I wouldn't be asking lol
OpenStudy (anonymous):
No! static friction is the force required to set the body in motion in our case it 's given as 258.0N
OpenStudy (anonymous):
Well they're asking from the coefficient of static friction?
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OpenStudy (anonymous):
coefficient of static friction=static friction force/normal reaction