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Physics 13 Online
OpenStudy (anonymous):

Forces: You discover that it takes 258.0 N to set a 40.0 kg crate in motion on a concrete surface. What is the coefficient of static friction for the crate?

OpenStudy (anonymous):

@ swin u need to know what plane u are working on is it an incline plane or an horizontal plane/

OpenStudy (anonymous):

coefficient of static friction=static frictional force/ normal rection

OpenStudy (anonymous):

I assume the plane is horizontal: the normal reaction=weight=mg ur

OpenStudy (anonymous):

got it buddy?

OpenStudy (anonymous):

@hubertH it doesn't say. so i assumed it was horrizontal

OpenStudy (anonymous):

so u knw how to get to the answer right?

OpenStudy (anonymous):

but is static friction only involved in inclined plane?

OpenStudy (anonymous):

No.. then I wouldn't be asking lol

OpenStudy (anonymous):

No! static friction is the force required to set the body in motion in our case it 's given as 258.0N

OpenStudy (anonymous):

Well they're asking from the coefficient of static friction?

OpenStudy (anonymous):

coefficient of static friction=static friction force/normal reaction

OpenStudy (anonymous):

for horizontal plane normal reaction=mg

OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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