Question

Simplify completely,

Answer 1

\[\frac{ 2x^2+13x+20 }{ x^2-5x-36 }\]

Answer 2

factorise denominator and nominator

Answer 3

how?

Answer 4

\[\frac{ (2x+5)(x+4) }{ (x-9)(x+4) }\]

Answer 5

2x^2+9/x^2-36?

Answer 6

No, cancel the x + 4 factor from the numerator and denominator.

Answer 7

what?

Answer 8

\[\frac{ (2x + 5)(x + 4) }{ (x - 9)(x + 4) }\] is the same as \[\frac{ (2x + 5) }{ (x - 9) } \times \frac{ (x + 4) }{ (x + 4) }\] and that last factor of (x + 4)/(x + 4) is "1". All with the usual restrictions, of course. And any number multiplied by 1 is the same number.

Answer 9

what do i do?

Answer 10

As mentioned before, cancel the x + 4 factor from the numerator and denominator. Last post shows you how.

Answer 11

oh, that was easy, thanks!