Question

New Question! :-)

Answer 1

[8.02] Factor completely: 2x3 + 6x2 + 2x + 6

2[(x + 3)(x2 + 1)]

(2x + 6)(x2 + 1)

(x + 3)(2x2 + 2)

2(x3 + 3x2 + x + 3)

Answer 2

Is it A?

Answer 3

How do you know it's A?

Answer 4

I think it's A, I don't know for sure. :-)

Answer 5

Did you expand it?

Answer 6

Um...no.

Answer 7

Try it.

Answer 8

What is expanding?

Answer 9

Kind of like simplify it.

Answer 10

Oh, well, the common factor is 2, so we divide all the numbers by 2?

Answer 11

Well, yeah. Because of this, we know it's not B or C.

Answer 12

But if you divide 2x3 by 2, don't you get x3, so it would actually be d?

Answer 13

Yeah, but is x³ + 3x² + x + 3 factorable?

Answer 14

Yeah, because of the 3x3 and 3.

Answer 15

If it is, then it is A.

Answer 16

So A is right?

Answer 17

If x³ + 3x² + x + 3 is factorable, yeah.

Answer 18

Well, is it? I thought it was.

Answer 19

I am still confused! :(