please help!!!! ---differential equations: x'=3x-2y and y'=2x-2y
Ok, and then what?
solving simultaneously
For x and y? Is x' = dx/dy and y' = dy/dx?
yes... that's correct
Hmm, I can see how to get an equation in x and y from that, but do you want numerical values for both x and y? I'll have to look at this a different way. Just a sec.
The first thing I thought of was that x' and y' are reciprocals, so you could do \(\large 3x-2y=(2x-2y)^{-1}\) and rearrange from there...
still confused...
Me too. I'm not sure exactly what you're looking for.
Is there any other information or detail in the question for what the answer should look like?
an example in class, she said solve one eqn... let's say y=.. differentiate it and substitute in eqn (2)
Ok, that sounds reasonable, being standard system solving procedure. That would look like this: \(\large x'=3x-2y \rightarrow y=(-1/2)(x'-3x)\) \(\large y'=2x-2y \rightarrow x=(1/2)(y'+2y)\) Differentiating x: \(\large x'=(1/2)(y''+2)\) Sub into other equation: \(\large y=(-1/2)((1/2)(y''+2)-3(1/2)(y'+2y))\) Simplify and rearange into a second-order DE. \(\large \)
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