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Mathematics 8 Online
OpenStudy (anonymous):

Another optimization problem. This one I really dont know how to do it :)

OpenStudy (anonymous):

OpenStudy (anonymous):

so I believe is equation is 10 (2x^2) + 2 (4xh) what to do with the h?

OpenStudy (sirm3d):

the correct expression should be \[10(x^2)+2(4xh)+2(2x^2)\] since the box is made of tin and velvet on its bottom

OpenStudy (anonymous):

isnt only the bottom is lined with velvet?

OpenStudy (sirm3d):

the expression represents the cost in making the box with velvet at the bottom, so this should be equated to the total cost given in the problem

OpenStudy (anonymous):

oh..or is it saying the box is first layered with tin, but the bottom has addition llayer of velvet?

OpenStudy (sirm3d):

tin layered with velvet

OpenStudy (sirm3d):

velvet on tin on the bottom, that's what i mean.

OpenStudy (anonymous):

ohh ok, yea, thats what i think. but that's what i did .. what do I do with the h?

OpenStudy (sirm3d):

uhm, solve h, substitute in the formula for the volume of the box, then maximize the volume of the box.

OpenStudy (anonymous):

oh ok, i will try it first, thanks

OpenStudy (sirm3d):

don't forget to convert $ to cents, since you are using cents in your equation for h.

OpenStudy (anonymous):

thks :/ i just realized i had the wrong units after i finished it lol

OpenStudy (sirm3d):

is it a typo error that velvet costs 10 cents/cm^3?

OpenStudy (asnaseer):

I think this question has more errors than just that typo

OpenStudy (asnaseer):

If you follow what it says, then @sirm3d has formulated the correct equation. However, solving that equation leads to a velvet cost of $0.57 which is not in any of the options. However, if you assume the box does NOT have a top, then we get a solution of $0.67 - which IS one of the options.

OpenStudy (asnaseer):

Unless I have made an error in my calculations?

OpenStudy (anonymous):

what did u get for ur x value?

OpenStudy (asnaseer):

for a closed box I got: \(x=\sqrt{\frac{120}{21}}\) for an open box I got: \(x=\sqrt{\frac{20}{3}}\)

OpenStudy (anonymous):

ok, then i believe the question suppose to be an open box.. it is 100% possible that they practice problems have mistakes :) thanks

OpenStudy (sirm3d):

mine are the same as @asnaseer

OpenStudy (anonymous):

can u show me how u did it..i'm 0.30 off...

OpenStudy (anonymous):

is h = 240 - 12x^2 / 8x

OpenStudy (asnaseer):

yw :) the main thing here is that you understand how to solve these types of questions. Matching the right answer is least thing you should worry about. :) for closed box, I got: \(h=\frac{120-7x^2}{4x}\) for open box: \(h=\frac{120-6x^2}{4x}\)

OpenStudy (asnaseer):

It might be better for you to show us your steps so that we can spot where you may have made a mistake.

OpenStudy (anonymous):

ohh ok i get it.. i spotted mine rightaway :) it's just i'm not totally 100% understand why sirm had that equation

OpenStudy (anonymous):

now i do thanks both of u

OpenStudy (anonymous):

keep forgetting the bottom has both velvet and tin

OpenStudy (asnaseer):

the bottom of the box has sides of length x. so it area is x^2 the vertical sides of the box (4 of them) each have an area of xh

OpenStudy (sirm3d):

i corrected your expression which represents the cost of the box. from you expression, i conclude that x is the side of the square and h is the height

OpenStudy (asnaseer):

so, assuming an open box, total surface area for tin would be: x^2 + 4xh and total surface area for velvet would be: x^2

OpenStudy (asnaseer):

so the total cost would be:\[2(x^2+4xh)+10x^2=240\]where I have converted everything to cents

OpenStudy (anonymous):

yea, now i really do get it :) i will just do both open box and closed box for more practice then!

OpenStudy (asnaseer):

good idea - its great to see someone who is eager to learn! :)

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