Question

I need to solve for x: log(base 5x + 9) (x^2 + 6x + 9) + log(base x+3) (5x^2 + 24x + 27) = 4

Answer 1

\[\log_{5x+9} (x^2+6x+9)+\log_{x+3} (5x^2+24x+27) = 4\]

Is that the question?

Answer 2

@lucenzo

Answer 3

yeah, that's it

Answer 4

They don't have the same base?

Answer 5

Darn... This complicates things...

Answer 6

Okay I would factor.

Answer 7

\[\log_{5x+9}(x+3)^{2}+\log_{x+3} ((5x+9)(x+3))\]

Answer 8

=4

Answer 9

Can you see anyway to simplify this? :) .

Answer 10

no, I have no idea

Answer 11

You have two logs multiplied. What can you do? :) .

Answer 12

This is a type of a bonus, so we never learned this (I thought of factoring but idk how to xD). Is it possible to get both logs to the same base? By putting them both to the power of (5x+9)(x+3)

Answer 13

They don't have the same base so you can't do "loga + logb = log(a*b)"

Answer 14

I meant for the right log :) .

Answer 15

OH

Answer 16

Ohh you need help factoring? Okay:

Answer 17

You do log (5x^2 + 24x + 27)/(x+3)