A triangle is inscribed on the quater- ellipse given by x^2 +4y^2 = 16 , x,y > 0 Find the greatest possible area of such triangle
Here is my work
Ah poopers, did we get the wrong answer last time love? D:
Is there a particular orientation we are to consider? Is therea a base of the triangle on the x-axis? The y-axis? Neither?
um yes, there is a picture, wait
no, but i still dont get it
sorry...i just dnt get these questions..
|dw:1351989871092:dw| like..i thought i understand it..but how come i still got the wrong answer
|dw:1351989984992:dw|it seems like you do want to think about where the base is, as was said ealrier
|dw:1351990091919:dw||dw:1351990112852:dw|
The area, then is what? 1/2 Base Height Base is half the length fo the major axis. What is that. Height is the y-coordiante of that apex point. What is that?
A= 1/2 bh , is it always equal to 1/2 xy
I know how to do this quesiton, but i feel like i need to understand the concept better other than just memorizing how to do it ><
Ok sorry about that, I setup the problem assuming it was a right triangle when we had originally done it, that was bad apparently ^^ heh
ohh ok, so it doesnt have to be a right angle triangle
ok, then i get it now thanks. I was wondering why is it right angle triangle..
I think the largest triangle is going to be a right triangle anyway
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