In the below system, solve for y in the first equation.

x + 3y = 6
2x – y = 10

Question

In the below system, solve for y in the first equation.

x + 3y = 6
2x – y = 10

anonymous · Answer

So the equation is 
x+3y=6, and you want to solve for y?

Just move everything that is not a y to the other side of the equals sign.
Standard procedure.

anonymous · Answer

y = (6 - x)/3

anonymous · Answer

@xxmileyxxd This
"so y=6-x/3, or y=-x+6/3 so your left with y=2-x or y=-x+2"
Doesn't make sense. Can you explain further, please?

anonymous · Answer

xxmileyxxd is incorrect. You would not get "y=2-x or y=-x+2"

remember it's (6 - x) divided by 3. you cannot divide the 6 alone by 3. you need to divide the "x" as well.

so it would be: $$y = 2 - \frac{ 1 }{ 3 }x $$

anonymous · Answer

He's just solving for y, you move everything to one side to get your answer, than divide the 3 to the other side.

anonymous · Answer

^ yes, which would yield the following:

$\large x + 3y = 6 \rightarrow y=\frac{6-x}{3}$

In slope intercept form that would be $\large  y=-\frac{1}{3}x+2$.