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OpenStudy (calculusfunctions):
Simplify\[(-3x ^{4}y ^{-5})(4x ^{-3}y ^{2})\]Is this your question?
OpenStudy (anonymous):
yes it is
OpenStudy (anonymous):
how do i solve this problem
OpenStudy (calculusfunctions):
Do you know your exponent laws?
OpenStudy (calculusfunctions):
@jmays14 it's all multiplication. But first do you know the exponent law which states that when you multiply two powers with the same base, you add their exponents?
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OpenStudy (anonymous):
no i dont could you help me out
OpenStudy (calculusfunctions):
Sure. The product law states that when you multiply two powers with the same base, you add their exponents. e.g.\[x ^{a}\times x ^{b}=x ^{a +b}\]Understand?
OpenStudy (anonymous):
so im going to multiply 3 and 4
OpenStudy (anonymous):
how would i show my work
OpenStudy (calculusfunctions):
Step 1: (-3)(4) = ?
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OpenStudy (anonymous):
-12
OpenStudy (calculusfunctions):
Step 2:\[x ^{4}\times x ^{-3}=?\]
OpenStudy (anonymous):
7
OpenStudy (calculusfunctions):
That's a -3. The feature here makes the exponents 2 and 3 look alike.
OpenStudy (calculusfunctions):
No,! Remember you add the exponents. Try again.
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OpenStudy (anonymous):
2
OpenStudy (calculusfunctions):
\[x ^{4}\times x ^{-3}=x ^{4+(-3)}=?\]
OpenStudy (calculusfunctions):
No, I told you that its a -3, not a -2. Please pay attention!!!
OpenStudy (anonymous):
1
OpenStudy (calculusfunctions):
so you mean x, right?
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OpenStudy (anonymous):
yea
OpenStudy (calculusfunctions):
Step 3:\[y ^{-5}\times y ^{2}=?\]This time that exponent is 2.
OpenStudy (anonymous):
-7
OpenStudy (calculusfunctions):
\[y ^{-5}\times y ^{2}=y ^{-5+2}=?\]
OpenStudy (anonymous):
-3
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OpenStudy (calculusfunctions):
you mean\[y ^{-3}\]right?
OpenStudy (anonymous):
yes now how do i put it all together
OpenStudy (calculusfunctions):
Now when you multiply the results of all three steps, what do you get?
OpenStudy (anonymous):
how do you put it all together
OpenStudy (calculusfunctions):
I just told you, multiply the results of all three steps.
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OpenStudy (anonymous):
i got 12 can you right it out for me so ill kno how to do the next 1
OpenStudy (calculusfunctions):
The answer is\[-12xy ^{-3}\]or\[\frac{ -12x }{ y ^{3} }\]
Remember that exponent that looks like a 2, is actually a 3.