Mathematics
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OpenStudy (anonymous):
Find the derivative of the function.
y = a7 + cos7 x
is this righ? -7cos^6x sinx
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OpenStudy (baldymcgee6):
What is a?
hartnn (hartnn):
yes.
hartnn (hartnn):
a must be constant
OpenStudy (anonymous):
a^7+cos^7 X ( X is not with 7)
OpenStudy (baldymcgee6):
Then yes, it's correct :)
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hartnn (hartnn):
you are correct.
OpenStudy (baldymcgee6):
you can write that as (cos(x))^7
OpenStudy (baldymcgee6):
for future reference :D
OpenStudy (anonymous):
no its not lol
OpenStudy (anonymous):
im doing an anline quiz
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OpenStudy (anonymous):
that wasnt the answer guys
OpenStudy (baldymcgee6):
maybe you didn't type it in right.
hartnn (hartnn):
or using latex, u could write as
\[\cos^7x\]
`\[\cos^7x\]`
what were the options? i don't see any mistake here....
OpenStudy (anonymous):
hartnn (hartnn):
u should have put brackets!
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hartnn (hartnn):
-7(cos^6 x)( sinx)
OpenStudy (anonymous):
can u guys help me with this question
OpenStudy (anonymous):
OpenStudy (baldymcgee6):
How would you do it?
OpenStudy (anonymous):
i have no idea
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OpenStudy (anonymous):
baldymcgee6
OpenStudy (baldymcgee6):
[e^u]' = e^u * du/dx
OpenStudy (baldymcgee6):
[e^(4tsin(2t))]' = e^(4tsin(2t)) * [4tsin(2t)]'
OpenStudy (anonymous):
okayyy...
OpenStudy (baldymcgee6):
that's not the final answer, you still need to differentiate the rest..
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OpenStudy (baldymcgee6):
3pi/4
OpenStudy (anonymous):
whats the derivative of sin2t
OpenStudy (baldymcgee6):
What do you think it is?
OpenStudy (baldymcgee6):
use the chain rule
OpenStudy (anonymous):
-cos2t
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OpenStudy (baldymcgee6):
[sin(2t)]' = cos(2t) * [2t]'