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Mathematics 10 Online
OpenStudy (anonymous):

can somebody please help me understand what happening in the attached.

OpenStudy (anonymous):

article 64

OpenStudy (chihiroasleaf):

are you asking the explanation of each step?

OpenStudy (anonymous):

yes

OpenStudy (chihiroasleaf):

first, we let \[z=\frac{ x+y }{ x-y }\] so, we can rewrite the equation as \[2z+\frac{ 10 }{ z }=9\]

OpenStudy (anonymous):

now 10((x-y)/(x+y))=10/z

OpenStudy (chihiroasleaf):

consider that \[z= \frac{ x+y }{ x-y }\] so, what is \[\frac{1}{z}\] ?

OpenStudy (anonymous):

raised to the -1 power

OpenStudy (chihiroasleaf):

hhmm..., \[z=\frac{ x+y }{ x-y }\] so, \[\frac{ 1 }{ z }=\frac{ 1 }{ \frac{ x+y }{ x-y} }=1\times \frac{ x-y }{ x+y }= \frac{ x-y }{ x+y }\] therefore, \[10 \frac{ x-y }{ x+y } =10 \times \frac{1}{z} = \frac{10}{z} \]

OpenStudy (anonymous):

so (x-y)/(x+y)=1/z

OpenStudy (anonymous):

thanks for clearing that up for me.

OpenStudy (chihiroasleaf):

you're welcome..., just ask if you still confused about the rest :)

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