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Disssolving 120g of urea(mol wt 60)in 1000g of water gave a sol of density 1.15g/ml.the molarity of the solution is ....? please tell me detailed steps.
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Please tell me soon
Do u knw wat is Molarity..?
\[D=\frac{ M }{ V }\] \[V=\frac{ M }{ D }\] M = 1000 + 120 = 1120gm
but the answer is 2.05M
Lol....First Find V then use Molarity = no of moles of solute / Volume (L)
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how to find V
hm..thats wat i have Given u.....)
1.15 g/ml = 1150 g/L
\[V = 1120/1150 = 0.973L\] no of moles = 120/60 = 2
\[M = 2/0.973 = 2.05M\]
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hope u got it...)
tks
Welcome..)
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please wait i have to ask u another question
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