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Differentiate f(x)=logax.
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\[f(x)=\log _{a}X\]
i think its 1/x but that is not right
use the property of log \(\huge\log_ab=\frac{\ln b}{\ln a}\)
then differentiate
\[\log_{a} x = \frac{\ln x}{\ln a}\] Note that ln a is constant.
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remember that a is constant
Do you know the derivative of ln x?
@Brooke_army are u getting, whats is going on ?
yes sort of
so what would be your answer ?
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i have no idea
how do you fine the derivative of ln x?
its pretty standard its 1/x
now ?
is it a/x?
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umm.. nopes since ln a is constant, you can write f'(x) = (log_a x )' = ( ln x/ ln a)' = (1/ln a) (ln x)' and (ln x)'=1/x
ok?
yes that makes sense now. Thanks for the help
finally its 1/ (x ln a). welcome ^_^
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